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114013454333 is a prime number
BaseRepresentation
bin110101000101110111…
…0110011111111111101
3101220021210102120200212
41222023232303333331
53331444421014313
6124213240002205
711144234241332
oct1521356637775
9356253376625
10114013454333
1144397693819
121a11aa60365
13a99cb4c55c
14573823a989
152e746293a8
hex1a8bbb3ffd

114013454333 has 2 divisors, whose sum is σ = 114013454334. Its totient is φ = 114013454332.

The previous prime is 114013454239. The next prime is 114013454407. The reversal of 114013454333 is 333454310411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113759147524 + 254306809 = 337282^2 + 15947^2 .

It is an emirp because it is prime and its reverse (333454310411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114013454333 - 220 = 114012405757 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 114013454333.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114013451333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006727166 + 57006727167.

It is an arithmetic number, because the mean of its divisors is an integer number (57006727167).

Almost surely, 2114013454333 is an apocalyptic number.

It is an amenable number.

114013454333 is a deficient number, since it is larger than the sum of its proper divisors (1).

114013454333 is an equidigital number, since it uses as much as digits as its factorization.

114013454333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 114013454333 its reverse (333454310411), we get a palindrome (447467764744).

The spelling of 114013454333 in words is "one hundred fourteen billion, thirteen million, four hundred fifty-four thousand, three hundred thirty-three".