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11401410131 = 82731378147
BaseRepresentation
bin10101001111001001…
…11011011001010011
31002102120202122102022
422213210323121103
5141322230111011
65123203442055
7552352246526
oct124744733123
932376678368
1011401410131
114920887201
12226238632b
1310c9140a37
147a2320bbd
1546ae308db
hex2a793b653

11401410131 has 4 divisors (see below), whose sum is σ = 11402796552. Its totient is φ = 11400023712.

The previous prime is 11401410127. The next prime is 11401410133. The reversal of 11401410131 is 13101410411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11401410131 - 22 = 11401410127 is a prime.

It is a super-2 number, since 2×114014101312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11401410133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 680801 + ... + 697346.

It is an arithmetic number, because the mean of its divisors is an integer number (2850699138).

Almost surely, 211401410131 is an apocalyptic number.

11401410131 is a deficient number, since it is larger than the sum of its proper divisors (1386421).

11401410131 is an equidigital number, since it uses as much as digits as its factorization.

11401410131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1386420.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11401410131 its reverse (13101410411), we get a palindrome (24502820542).

The spelling of 11401410131 in words is "eleven billion, four hundred one million, four hundred ten thousand, one hundred thirty-one".

Divisors: 1 8273 1378147 11401410131