Base | Representation |
---|---|
bin | 110101000101111000… |
… | …1101010100001100001 |
3 | 101220021211211120020111 |
4 | 1222023301222201201 |
5 | 3332000113430303 |
6 | 124213304011321 |
7 | 11144243504101 |
oct | 1521361524141 |
9 | 356254746214 |
10 | 114014201953 |
11 | 44398054493 |
12 | 1a11b160b41 |
13 | a9a0051932 |
14 | 5738393201 |
15 | 2e74725b6d |
hex | 1a8bc6a861 |
114014201953 has 2 divisors, whose sum is σ = 114014201954. Its totient is φ = 114014201952.
The previous prime is 114014201947. The next prime is 114014202011. The reversal of 114014201953 is 359102410411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70719828624 + 43294373329 = 265932^2 + 208073^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114014201953 is a prime.
It is not a weakly prime, because it can be changed into another prime (114014201933) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57007100976 + 57007100977.
It is an arithmetic number, because the mean of its divisors is an integer number (57007100977).
Almost surely, 2114014201953 is an apocalyptic number.
It is an amenable number.
114014201953 is a deficient number, since it is larger than the sum of its proper divisors (1).
114014201953 is an equidigital number, since it uses as much as digits as its factorization.
114014201953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 31.
The spelling of 114014201953 in words is "one hundred fourteen billion, fourteen million, two hundred one thousand, nine hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.025 sec. • engine limits •