11401433 has 4 divisors (see below), whose sum is σ = 11411940. Its totient is φ = 11390928.

The previous prime is 11401427. The next prime is 11401447. The reversal of 11401433 is 33410411.

11401433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 33410411 = 151 ⋅221261.

It can be written as a sum of positive squares in 2 ways, for example, as 10549504 + 851929 = 3248^2 + 923^2 .

It is a cyclic number.

It is not a de Polignac number, because 11401433 - 2⁴ = 11401417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11401483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3410 + ... + 5867.

It is an arithmetic number, because the mean of its divisors is an integer number (2852985).

Almost surely, 2^11401433 is an apocalyptic number.

It is an amenable number.

11401433 is a deficient number, since it is larger than the sum of its proper divisors (10507).

11401433 is an equidigital number, since it uses as much as digits as its factorization.

11401433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10506.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 11401433 is about 3376.6008055439. The cubic root of 11401433 is about 225.0711412899.

Adding to 11401433 its reverse (33410411), we get a palindrome (44811844).

The spelling of 11401433 in words is "eleven million, four hundred one thousand, four hundred thirty-three".