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11401434001 is a prime number
BaseRepresentation
bin10101001111001010…
…00001001110010001
31002102120210212011101
422213211001032101
5141322231342001
65123204144401
7552352406236
oct124745011621
932376725141
1011401434001
1149208a3131
122262398101
1310c914b869
147a232978d
1546ae37a01
hex2a7941391

11401434001 has 2 divisors, whose sum is σ = 11401434002. Its totient is φ = 11401434000.

The previous prime is 11401433999. The next prime is 11401434007. The reversal of 11401434001 is 10043410411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10394006401 + 1007427600 = 101951^2 + 31740^2 .

It is a cyclic number.

It is not a de Polignac number, because 11401434001 - 21 = 11401433999 is a prime.

Together with 11401433999, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 11401434001.

It is not a weakly prime, because it can be changed into another prime (11401434007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700717000 + 5700717001.

It is an arithmetic number, because the mean of its divisors is an integer number (5700717001).

Almost surely, 211401434001 is an apocalyptic number.

It is an amenable number.

11401434001 is a deficient number, since it is larger than the sum of its proper divisors (1).

11401434001 is an equidigital number, since it uses as much as digits as its factorization.

11401434001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 11401434001 its reverse (10043410411), we get a palindrome (21444844412).

The spelling of 11401434001 in words is "eleven billion, four hundred one million, four hundred thirty-four thousand, one".