Base | Representation |
---|---|
bin | 10000100101111001011… |
… | …011011000010011011101 |
3 | 11001000001202010220211202 |
4 | 100211321123120103131 |
5 | 122140114102212023 |
6 | 2231445143125245 |
7 | 145243210204166 |
oct | 20457133302335 |
9 | 4030052126752 |
10 | 1140203554013 |
11 | 3aa6151aa197 |
12 | 164b8ba43825 |
13 | 836a008a6a4 |
14 | 3d286b0076d |
15 | 1e9d5295128 |
hex | 109796d84dd |
1140203554013 has 2 divisors, whose sum is σ = 1140203554014. Its totient is φ = 1140203554012.
The previous prime is 1140203553997. The next prime is 1140203554019. The reversal of 1140203554013 is 3104553020411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1130983329529 + 9220224484 = 1063477^2 + 96022^2 .
It is a cyclic number.
It is not a de Polignac number, because 1140203554013 - 24 = 1140203553997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1140203554019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570101777006 + 570101777007.
It is an arithmetic number, because the mean of its divisors is an integer number (570101777007).
Almost surely, 21140203554013 is an apocalyptic number.
It is an amenable number.
1140203554013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140203554013 is an equidigital number, since it uses as much as digits as its factorization.
1140203554013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 1140203554013 its reverse (3104553020411), we get a palindrome (4244756574424).
The spelling of 1140203554013 in words is "one trillion, one hundred forty billion, two hundred three million, five hundred fifty-four thousand, thirteen".
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