Base | Representation |
---|---|
bin | 10101001111001111… |
… | …00110110000000011 |
3 | 1002102122002022012120 |
4 | 22213213212300003 |
5 | 141322420041003 |
6 | 5123230455323 |
7 | 552361232022 |
oct | 124747466003 |
9 | 32378068176 |
10 | 11402112003 |
11 | 4921216567 |
12 | 2262664543 |
13 | 10c9328349 |
14 | 7a24648b9 |
15 | 46b01d853 |
hex | 2a79e6c03 |
11402112003 has 4 divisors (see below), whose sum is σ = 15202816008. Its totient is φ = 7601408000.
The previous prime is 11402111989. The next prime is 11402112047. The reversal of 11402112003 is 30021120411.
11402112003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11402112003 - 29 = 11402111491 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11402132003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1900351998 + ... + 1900352003.
It is an arithmetic number, because the mean of its divisors is an integer number (3800704002).
Almost surely, 211402112003 is an apocalyptic number.
11402112003 is a deficient number, since it is larger than the sum of its proper divisors (3800704005).
11402112003 is an equidigital number, since it uses as much as digits as its factorization.
11402112003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3800704004.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 11402112003 its reverse (30021120411), we get a palindrome (41423232414).
The spelling of 11402112003 in words is "eleven billion, four hundred two million, one hundred twelve thousand, three".
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