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11402112003 = 33800704001
BaseRepresentation
bin10101001111001111…
…00110110000000011
31002102122002022012120
422213213212300003
5141322420041003
65123230455323
7552361232022
oct124747466003
932378068176
1011402112003
114921216567
122262664543
1310c9328349
147a24648b9
1546b01d853
hex2a79e6c03

11402112003 has 4 divisors (see below), whose sum is σ = 15202816008. Its totient is φ = 7601408000.

The previous prime is 11402111989. The next prime is 11402112047. The reversal of 11402112003 is 30021120411.

11402112003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11402112003 - 29 = 11402111491 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11402132003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1900351998 + ... + 1900352003.

It is an arithmetic number, because the mean of its divisors is an integer number (3800704002).

Almost surely, 211402112003 is an apocalyptic number.

11402112003 is a deficient number, since it is larger than the sum of its proper divisors (3800704005).

11402112003 is an equidigital number, since it uses as much as digits as its factorization.

11402112003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3800704004.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 11402112003 its reverse (30021120411), we get a palindrome (41423232414).

The spelling of 11402112003 in words is "eleven billion, four hundred two million, one hundred twelve thousand, three".

Divisors: 1 3 3800704001 11402112003