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114021131153 is a prime number
BaseRepresentation
bin110101000110000110…
…0000110001110010001
3101220022022212121022112
41222030030012032101
53332003402144103
6124214112315105
711144356423616
oct1521414061621
9356268777275
10114021131153
11443a0a574a6
121a121542a95
13a9a1609857
14573927850d
152e75143cd8
hex1a8c306391

114021131153 has 2 divisors, whose sum is σ = 114021131154. Its totient is φ = 114021131152.

The previous prime is 114021131123. The next prime is 114021131177. The reversal of 114021131153 is 351131120411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62368569169 + 51652561984 = 249737^2 + 227272^2 .

It is an emirp because it is prime and its reverse (351131120411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114021131153 - 222 = 114016936849 is a prime.

It is not a weakly prime, because it can be changed into another prime (114021131123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57010565576 + 57010565577.

It is an arithmetic number, because the mean of its divisors is an integer number (57010565577).

Almost surely, 2114021131153 is an apocalyptic number.

It is an amenable number.

114021131153 is a deficient number, since it is larger than the sum of its proper divisors (1).

114021131153 is an equidigital number, since it uses as much as digits as its factorization.

114021131153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 114021131153 its reverse (351131120411), we get a palindrome (465152251564).

The spelling of 114021131153 in words is "one hundred fourteen billion, twenty-one million, one hundred thirty-one thousand, one hundred fifty-three".