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1140212551 is a prime number
BaseRepresentation
bin100001111110110…
…0100001101000111
32221110111210120111
41003331210031013
54313343300201
6305050413451
740153434562
oct10375441507
92843453514
101140212551
11535690625
12279a31287
131522c01aa
14ab6094d9
156a17ab51
hex43f64347

1140212551 has 2 divisors, whose sum is σ = 1140212552. Its totient is φ = 1140212550.

The previous prime is 1140212543. The next prime is 1140212569. The reversal of 1140212551 is 1552120411.

It is a weak prime.

It is an emirp because it is prime and its reverse (1552120411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1140212551 - 23 = 1140212543 is a prime.

It is a super-2 number, since 2×11402125512 = 2600169322915855202, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1140212351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570106275 + 570106276.

It is an arithmetic number, because the mean of its divisors is an integer number (570106276).

Almost surely, 21140212551 is an apocalyptic number.

1140212551 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140212551 is an equidigital number, since it uses as much as digits as its factorization.

1140212551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 400, while the sum is 22.

The square root of 1140212551 is about 33767.0334942233. The cubic root of 1140212551 is about 1044.7088467969.

Adding to 1140212551 its reverse (1552120411), we get a palindrome (2692332962).

The spelling of 1140212551 in words is "one billion, one hundred forty million, two hundred twelve thousand, five hundred fifty-one".