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114023114314 = 257011557157
BaseRepresentation
bin110101000110001001…
…1101010011001001010
3101220022110121100200221
41222030103222121022
53332004404124224
6124214223020254
711144412323464
oct1521423523112
9356273540627
10114023114314
11443a209147a
121a12213a68a
13a9a1b52415
145739633134
152e753d66e4
hex1a8c4ea64a

114023114314 has 4 divisors (see below), whose sum is σ = 171034671474. Its totient is φ = 57011557156.

The previous prime is 114023114297. The next prime is 114023114333. The reversal of 114023114314 is 413411320411.

114023114314 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 95038408089 + 18984706225 = 308283^2 + 137785^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28505778577 + ... + 28505778580.

Almost surely, 2114023114314 is an apocalyptic number.

114023114314 is a deficient number, since it is larger than the sum of its proper divisors (57011557160).

114023114314 is an equidigital number, since it uses as much as digits as its factorization.

114023114314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57011557159.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 114023114314 its reverse (413411320411), we get a palindrome (527434434725).

The spelling of 114023114314 in words is "one hundred fourteen billion, twenty-three million, one hundred fourteen thousand, three hundred fourteen".

Divisors: 1 2 57011557157 114023114314