Base | Representation |
---|---|
bin | 110101000110001001… |
… | …1101010011001001010 |
3 | 101220022110121100200221 |
4 | 1222030103222121022 |
5 | 3332004404124224 |
6 | 124214223020254 |
7 | 11144412323464 |
oct | 1521423523112 |
9 | 356273540627 |
10 | 114023114314 |
11 | 443a209147a |
12 | 1a12213a68a |
13 | a9a1b52415 |
14 | 5739633134 |
15 | 2e753d66e4 |
hex | 1a8c4ea64a |
114023114314 has 4 divisors (see below), whose sum is σ = 171034671474. Its totient is φ = 57011557156.
The previous prime is 114023114297. The next prime is 114023114333. The reversal of 114023114314 is 413411320411.
114023114314 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 95038408089 + 18984706225 = 308283^2 + 137785^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28505778577 + ... + 28505778580.
Almost surely, 2114023114314 is an apocalyptic number.
114023114314 is a deficient number, since it is larger than the sum of its proper divisors (57011557160).
114023114314 is an equidigital number, since it uses as much as digits as its factorization.
114023114314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57011557159.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 114023114314 its reverse (413411320411), we get a palindrome (527434434725).
The spelling of 114023114314 in words is "one hundred fourteen billion, twenty-three million, one hundred fourteen thousand, three hundred fourteen".
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