Base | Representation |
---|---|
bin | 10101001111010000… |
… | …11100011101111111 |
3 | 1002102122111111000202 |
4 | 22213220130131333 |
5 | 141322444111111 |
6 | 5123235314115 |
7 | 552363136346 |
oct | 124750343577 |
9 | 32378444022 |
10 | 11402332031 |
11 | 4921356902 |
12 | 226274b93b |
13 | 10c93a453c |
14 | 7a24c0b5d |
15 | 46b063b3b |
hex | 2a7a1c77f |
11402332031 has 2 divisors, whose sum is σ = 11402332032. Its totient is φ = 11402332030.
The previous prime is 11402332013. The next prime is 11402332061. The reversal of 11402332031 is 13023320411.
Together with previous prime (11402332013) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11402332031 is a prime.
It is a super-2 number, since 2×114023320312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11402331994 and 11402332012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11402332061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701166015 + 5701166016.
It is an arithmetic number, because the mean of its divisors is an integer number (5701166016).
Almost surely, 211402332031 is an apocalyptic number.
11402332031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11402332031 is an equidigital number, since it uses as much as digits as its factorization.
11402332031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 11402332031 its reverse (13023320411), we get a palindrome (24425652442).
The spelling of 11402332031 in words is "eleven billion, four hundred two million, three hundred thirty-two thousand, thirty-one".
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