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11402403143 = 791977191019
BaseRepresentation
bin10101001111010001…
…01101110101000111
31002102122122002120112
422213220231311013
5141323003400033
65123241023235
7552363553565
oct124750556507
932378562515
1011402403143
1149213a527a
122262784b1b
1310c93caa11
147a24dca35
1546b079c48
hex2a7a2dd47

11402403143 has 16 divisors (see below), whose sum is σ = 11632896000. Its totient is φ = 11174366112.

The previous prime is 11402403097. The next prime is 11402403163. The reversal of 11402403143 is 34130420411.

It is a cyclic number.

It is not a de Polignac number, because 11402403143 - 218 = 11402140999 is a prime.

It is a super-3 number, since 3×114024031433 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11402403163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11189288 + ... + 11190306.

It is an arithmetic number, because the mean of its divisors is an integer number (727056000).

Almost surely, 211402403143 is an apocalyptic number.

11402403143 is a deficient number, since it is larger than the sum of its proper divisors (230492857).

11402403143 is a wasteful number, since it uses less digits than its factorization.

11402403143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2014.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 11402403143 its reverse (34130420411), we get a palindrome (45532823554).

The spelling of 11402403143 in words is "eleven billion, four hundred two million, four hundred three thousand, one hundred forty-three".

Divisors: 1 79 197 719 1019 15563 56801 80501 141643 200743 732661 11189797 15858697 57880219 144334217 11402403143