Base | Representation |
---|---|
bin | 110101000110001011… |
… | …1011100000111011101 |
3 | 101220022112110122212021 |
4 | 1222030113130013131 |
5 | 3332010132320123 |
6 | 124214300140141 |
7 | 11144423616202 |
oct | 1521427340735 |
9 | 356275418767 |
10 | 114024104413 |
11 | 443a26a833a |
12 | 1a122537651 |
13 | a9a210ac8b |
14 | 573980dca9 |
15 | 2e7552ec5d |
hex | 1a8c5dc1dd |
114024104413 has 4 divisors (see below), whose sum is σ = 114262151040. Its totient is φ = 113786057788.
The previous prime is 114024104353. The next prime is 114024104501. The reversal of 114024104413 is 314401420411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114024104413 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114024104113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119022595 + ... + 119023552.
It is an arithmetic number, because the mean of its divisors is an integer number (28565537760).
Almost surely, 2114024104413 is an apocalyptic number.
It is an amenable number.
114024104413 is a deficient number, since it is larger than the sum of its proper divisors (238046627).
114024104413 is an equidigital number, since it uses as much as digits as its factorization.
114024104413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 238046626.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 114024104413 its reverse (314401420411), we get a palindrome (428425524824).
The spelling of 114024104413 in words is "one hundred fourteen billion, twenty-four million, one hundred four thousand, four hundred thirteen".
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