11402444133 has 24 divisors (see below), whose sum is σ = 16551242136. Its totient is φ = 7564300800.

The previous prime is 11402444129. The next prime is 11402444147. The reversal of 11402444133 is 33144420411.

11402444133 is a `hidden beast` number, since 1 + 1 + 4 + 0 + 244 + 413 + 3 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 6614080929 + 4788363204 = 81327^2 + 69198^2 .

It is not a de Polignac number, because 11402444133 - 2² = 11402444129 is a prime.

It is a super-2 number, since 2×11402444133² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11402444097 and 11402444106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11402444173) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2164723 + ... + 2169983.

It is an arithmetic number, because the mean of its divisors is an integer number (689635089).

Almost surely, 2^11402444133 is an apocalyptic number.

It is an amenable number.

11402444133 is a deficient number, since it is larger than the sum of its proper divisors (5148798003).

11402444133 is a wasteful number, since it uses less digits than its factorization.

11402444133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6405 (or 6402 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 11402444133 its reverse (33144420411), we get a palindrome (44546864544).

It can be divided in two parts, 11402 and 444133, that added together give a triangular number (455535 = T₉₅₄).

The spelling of 11402444133 in words is "eleven billion, four hundred two million, four hundred forty-four thousand, one hundred thirty-three".