Base | Representation |
---|---|
bin | 1010010111101101011010… |
… | …1001001011110100001111 |
3 | 1111101001200221122120121212 |
4 | 2211323112221023310033 |
5 | 2443304201221332421 |
6 | 40130113254045035 |
7 | 2254541125405601 |
oct | 245732651136417 |
9 | 44331627576555 |
10 | 11402444324111 |
11 | 36a6827618185 |
12 | 1341a5364977b |
13 | 649327299b09 |
14 | 2b5c4a215171 |
15 | 14b90c981e5b |
hex | a5ed6a4bd0f |
11402444324111 has 4 divisors (see below), whose sum is σ = 11415749394192. Its totient is φ = 11389139254032.
The previous prime is 11402444324099. The next prime is 11402444324113. The reversal of 11402444324111 is 11142344420411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11402444324111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11402444324113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6652533755 + ... + 6652535468.
It is an arithmetic number, because the mean of its divisors is an integer number (2853937348548).
Almost surely, 211402444324111 is an apocalyptic number.
11402444324111 is a deficient number, since it is larger than the sum of its proper divisors (13305070081).
11402444324111 is an equidigital number, since it uses as much as digits as its factorization.
11402444324111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13305070080.
The product of its (nonzero) digits is 12288, while the sum is 32.
Adding to 11402444324111 its reverse (11142344420411), we get a palindrome (22544788744522).
The spelling of 11402444324111 in words is "eleven trillion, four hundred two billion, four hundred forty-four million, three hundred twenty-four thousand, one hundred eleven".
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