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114024520541471 is a prime number
BaseRepresentation
bin11001111011010001100111…
…000010101110010100011111
3112221201122012212222001101212
4121323101213002232110133
5104421134204224311341
61042302050330055035
733005666625633041
oct3173214702562437
9487648185861355
10114024520541471
1133371589261571
121095687127a47b
134b8160a191017
142022b5da9ba91
15d2b08d2335eb
hex67b4670ae51f

114024520541471 has 2 divisors, whose sum is σ = 114024520541472. Its totient is φ = 114024520541470.

The previous prime is 114024520541443. The next prime is 114024520541567. The reversal of 114024520541471 is 174145025420411.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114024520541471 is a prime.

It is a super-3 number, since 3×1140245205414713 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114024520541441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57012260270735 + 57012260270736.

It is an arithmetic number, because the mean of its divisors is an integer number (57012260270736).

Almost surely, 2114024520541471 is an apocalyptic number.

114024520541471 is a deficient number, since it is larger than the sum of its proper divisors (1).

114024520541471 is an equidigital number, since it uses as much as digits as its factorization.

114024520541471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 179200, while the sum is 41.

Adding to 114024520541471 its reverse (174145025420411), we get a palindrome (288169545961882).

The spelling of 114024520541471 in words is "one hundred fourteen trillion, twenty-four billion, five hundred twenty million, five hundred forty-one thousand, four hundred seventy-one".