Base | Representation |
---|---|
bin | 10000100101111011111… |
… | …011100100000101110011 |
3 | 11001000011200011022002202 |
4 | 100211323323210011303 |
5 | 122140210324422311 |
6 | 2231453243133415 |
7 | 145244230134644 |
oct | 20457373440563 |
9 | 4030150138082 |
10 | 1140245545331 |
11 | 3aa63697a962 |
12 | 164ba1b1426b |
13 | 836a89a0719 |
14 | 3d28c5116cb |
15 | 1e9d8cdbe3b |
hex | 1097bee4173 |
1140245545331 has 2 divisors, whose sum is σ = 1140245545332. Its totient is φ = 1140245545330.
The previous prime is 1140245545247. The next prime is 1140245545333. The reversal of 1140245545331 is 1335455420411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1140245545331 - 218 = 1140245283187 is a prime.
It is a super-2 number, since 2×11402455453312 (a number of 25 digits) contains 22 as substring.
Together with 1140245545333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1140245545333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570122772665 + 570122772666.
It is an arithmetic number, because the mean of its divisors is an integer number (570122772666).
Almost surely, 21140245545331 is an apocalyptic number.
1140245545331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140245545331 is an equidigital number, since it uses as much as digits as its factorization.
1140245545331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144000, while the sum is 38.
The spelling of 1140245545331 in words is "one trillion, one hundred forty billion, two hundred forty-five million, five hundred forty-five thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •