Base | Representation |
---|---|
bin | 11001111011010010011110… |
… | …000011010001100001101011 |
3 | 112221201201121012112202222010 |
4 | 121323102132003101201223 |
5 | 104421143102004320210 |
6 | 1042302322054531003 |
7 | 33006031533241434 |
oct | 3173223603214153 |
9 | 487651535482863 |
10 | 114025443432555 |
11 | 33371a121a9276 |
12 | 10956a8a366a63 |
13 | 4b81726440a15 |
14 | 2022c0a49648b |
15 | d2b0e4282920 |
hex | 67b49e0d186b |
114025443432555 has 32 divisors (see below), whose sum is σ = 182504897725248. Its totient is φ = 60792177600000.
The previous prime is 114025443432493. The next prime is 114025443432557. The reversal of 114025443432555 is 555234344520411.
It is a happy number.
It is not a de Polignac number, because 114025443432555 - 216 = 114025443367019 is a prime.
It is not an unprimeable number, because it can be changed into a prime (114025443432557) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 498028605 + ... + 498257505.
It is an arithmetic number, because the mean of its divisors is an integer number (5703278053914).
Almost surely, 2114025443432555 is an apocalyptic number.
114025443432555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114025443432555 is a deficient number, since it is larger than the sum of its proper divisors (68479454292693).
114025443432555 is a wasteful number, since it uses less digits than its factorization.
114025443432555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 240447.
The product of its (nonzero) digits is 5760000, while the sum is 48.
Adding to 114025443432555 its reverse (555234344520411), we get a palindrome (669259787952966).
The spelling of 114025443432555 in words is "one hundred fourteen trillion, twenty-five billion, four hundred forty-three million, four hundred thirty-two thousand, five hundred fifty-five".
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