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1140301431313 = 11103663766483
BaseRepresentation
bin10000100101111111010…
…000110000001000010001
311001000022120022121020221
4100211333100300020101
5122140314131300223
62231503001033041
7145245506145562
oct20457720601021
94030276277227
101140301431313
113aa665480920
12164bb8785781
13836b7439c55
143d295adc169
151e9ddb7ab5d
hex1097f430211

1140301431313 has 4 divisors (see below), whose sum is σ = 1243965197808. Its totient is φ = 1036637664820.

The previous prime is 1140301431253. The next prime is 1140301431329. The reversal of 1140301431313 is 3131341030411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1140301431313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1140301437313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51831883231 + ... + 51831883252.

It is an arithmetic number, because the mean of its divisors is an integer number (310991299452).

Almost surely, 21140301431313 is an apocalyptic number.

It is an amenable number.

1140301431313 is a deficient number, since it is larger than the sum of its proper divisors (103663766495).

1140301431313 is a wasteful number, since it uses less digits than its factorization.

1140301431313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103663766494.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1140301431313 its reverse (3131341030411), we get a palindrome (4271642461724).

The spelling of 1140301431313 in words is "one trillion, one hundred forty billion, three hundred one million, four hundred thirty-one thousand, three hundred thirteen".

Divisors: 1 11 103663766483 1140301431313