Base | Representation |
---|---|
bin | 10000100101111111010… |
… | …011011001010011100001 |
3 | 11001000022121121210210112 |
4 | 100211333103121103201 |
5 | 122140314320434012 |
6 | 2231503023541105 |
7 | 145245515063042 |
oct | 20457723312341 |
9 | 4030277553715 |
10 | 1140302124257 |
11 | 3aa6659044aa |
12 | 164bb8a5a795 |
13 | 836b762048a |
14 | 3d295c3c8c9 |
15 | 1e9ddc66122 |
hex | 1097f4d94e1 |
1140302124257 has 2 divisors, whose sum is σ = 1140302124258. Its totient is φ = 1140302124256.
The previous prime is 1140302124251. The next prime is 1140302124317. The reversal of 1140302124257 is 7524212030411.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1030730532001 + 109571592256 = 1015249^2 + 331016^2 .
It is a cyclic number.
It is not a de Polignac number, because 1140302124257 - 230 = 1139228382433 is a prime.
It is not a weakly prime, because it can be changed into another prime (1140302124251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570151062128 + 570151062129.
It is an arithmetic number, because the mean of its divisors is an integer number (570151062129).
Almost surely, 21140302124257 is an apocalyptic number.
It is an amenable number.
1140302124257 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140302124257 is an equidigital number, since it uses as much as digits as its factorization.
1140302124257 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 1140302124257 its reverse (7524212030411), we get a palindrome (8664514154668).
The spelling of 1140302124257 in words is "one trillion, one hundred forty billion, three hundred two million, one hundred twenty-four thousand, two hundred fifty-seven".
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