Base | Representation |
---|---|
bin | 11001111011010110111010… |
… | …010110001010100100011110 |
3 | 112221202011220121112201001201 |
4 | 121323112322112022210132 |
5 | 104421232334024123032 |
6 | 1042304431241430114 |
7 | 33006260660665603 |
oct | 3173267226124436 |
9 | 487664817481051 |
10 | 114030213114142 |
11 | 33373a3a5a5686 |
12 | 1095799b79b33a |
13 | 4b8200665b410 |
14 | 202313db226aa |
15 | d2b2c2d918e7 |
hex | 67b5ba58a91e |
114030213114142 has 16 divisors (see below), whose sum is σ = 184966978320432. Its totient is φ = 52410950167680.
The previous prime is 114030213114061. The next prime is 114030213114179. The reversal of 114030213114142 is 241411312030411.
It is a super-3 number, since 3×1140302131141423 (a number of 43 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 114030213114142.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9099117028 + ... + 9099129559.
It is an arithmetic number, because the mean of its divisors is an integer number (11560436145027).
Almost surely, 2114030213114142 is an apocalyptic number.
114030213114142 is a deficient number, since it is larger than the sum of its proper divisors (70936765206290).
114030213114142 is a wasteful number, since it uses less digits than its factorization.
114030213114142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18198246843.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 114030213114142 its reverse (241411312030411), we get a palindrome (355441525144553).
The spelling of 114030213114142 in words is "one hundred fourteen trillion, thirty billion, two hundred thirteen million, one hundred fourteen thousand, one hundred forty-two".
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