Base | Representation |
---|---|
bin | 1010010111101111101000… |
… | …1011001001110100101011 |
3 | 1111101010020111022222002201 |
4 | 2211323322023021310223 |
5 | 2443311411322301103 |
6 | 40130252350441031 |
7 | 2254561654262665 |
oct | 245737213116453 |
9 | 44333214288081 |
10 | 11403040431403 |
11 | 36a7003057435 |
12 | 1341b9b203177 |
13 | 6493c093191a |
14 | 2b5ca5467535 |
15 | 14b944e8151d |
hex | a5efa2c9d2b |
11403040431403 has 4 divisors (see below), whose sum is σ = 11403053813200. Its totient is φ = 11403027049608.
The previous prime is 11403040431337. The next prime is 11403040431407. The reversal of 11403040431403 is 30413404030411.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11403040431403 - 229 = 11402503560491 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11403040431407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5318928 + ... + 7148221.
It is an arithmetic number, because the mean of its divisors is an integer number (2850763453300).
Almost surely, 211403040431403 is an apocalyptic number.
11403040431403 is a deficient number, since it is larger than the sum of its proper divisors (13381797).
11403040431403 is an equidigital number, since it uses as much as digits as its factorization.
11403040431403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13381796.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 11403040431403 its reverse (30413404030411), we get a palindrome (41816444461814).
The spelling of 11403040431403 in words is "eleven trillion, four hundred three billion, forty million, four hundred thirty-one thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •