Base | Representation |
---|---|
bin | 10101001111010110… |
… | …11000001100100011 |
3 | 1002102200221112210201 |
4 | 22213223120030203 |
5 | 141323143212323 |
6 | 5123304010031 |
7 | 552402521212 |
oct | 124753301443 |
9 | 32380845721 |
10 | 11403100963 |
11 | 4921831591 |
12 | 2262a60917 |
13 | 10c95b3527 |
14 | 7a2641079 |
15 | 46b1668ad |
hex | 2a7ad8323 |
11403100963 has 2 divisors, whose sum is σ = 11403100964. Its totient is φ = 11403100962.
The previous prime is 11403100957. The next prime is 11403100967. The reversal of 11403100963 is 36900130411.
11403100963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11403100963 is a prime.
It is not a weakly prime, because it can be changed into another prime (11403100967) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701550481 + 5701550482.
It is an arithmetic number, because the mean of its divisors is an integer number (5701550482).
Almost surely, 211403100963 is an apocalyptic number.
11403100963 is a deficient number, since it is larger than the sum of its proper divisors (1).
11403100963 is an equidigital number, since it uses as much as digits as its factorization.
11403100963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 28.
The spelling of 11403100963 in words is "eleven billion, four hundred three million, one hundred thousand, nine hundred sixty-three".
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