Base | Representation |
---|---|
bin | 110101000110011001… |
… | …0001010101110000011 |
3 | 101220100000122122011002 |
4 | 1222030302022232003 |
5 | 3332013431023133 |
6 | 124215110242215 |
7 | 11144540310533 |
oct | 1521462125603 |
9 | 356300578132 |
10 | 114031111043 |
11 | 443a6653543 |
12 | 1a12495636b |
13 | a9a36c2205 |
14 | 573a7154c3 |
15 | 2e75e65ce8 |
hex | 1a8cc8ab83 |
114031111043 has 2 divisors, whose sum is σ = 114031111044. Its totient is φ = 114031111042.
The previous prime is 114031110983. The next prime is 114031111057. The reversal of 114031111043 is 340111130411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114031111043 - 216 = 114031045507 is a prime.
It is a super-3 number, since 3×1140311110433 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (114031111093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57015555521 + 57015555522.
It is an arithmetic number, because the mean of its divisors is an integer number (57015555522).
Almost surely, 2114031111043 is an apocalyptic number.
114031111043 is a deficient number, since it is larger than the sum of its proper divisors (1).
114031111043 is an equidigital number, since it uses as much as digits as its factorization.
114031111043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 114031111043 its reverse (340111130411), we get a palindrome (454142241454).
The spelling of 114031111043 in words is "one hundred fourteen billion, thirty-one million, one hundred eleven thousand, forty-three".
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