11403119993 has 2 divisors, whose sum is σ = 11403119994. Its totient is φ = 11403119992.

The previous prime is 11403119983. The next prime is 11403120013. The reversal of 11403119993 is 39991130411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6820777744 + 4582342249 = 82588^2 + 67693^2 .

It is a cyclic number.

It is not a de Polignac number, because 11403119993 - 2⁴ = 11403119977 is a prime.

It is a super-2 number, since 2×11403119993² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11403119993.

It is not a weakly prime, because it can be changed into another prime (11403119953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701559996 + 5701559997.

It is an arithmetic number, because the mean of its divisors is an integer number (5701559997).

Almost surely, 2^11403119993 is an apocalyptic number.

It is an amenable number.

11403119993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11403119993 is an equidigital number, since it uses as much as digits as its factorization.

11403119993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26244, while the sum is 41.

The spelling of 11403119993 in words is "eleven billion, four hundred three million, one hundred nineteen thousand, nine hundred ninety-three".