Search a number
-
+
11403120013 is a prime number
BaseRepresentation
bin10101001111010110…
…11100110110001101
31002102200222111221021
422213223130312031
5141323144320023
65123304234141
7552402630565
oct124753346615
932380874837
1011403120013
11492184492a
122262a6b951
1310c95bc0bc
147a2647da5
1546b16c35d
hex2a7adcd8d

11403120013 has 2 divisors, whose sum is σ = 11403120014. Its totient is φ = 11403120012.

The previous prime is 11403119993. The next prime is 11403120017. The reversal of 11403120013 is 31002130411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8630781604 + 2772338409 = 92902^2 + 52653^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11403120013 is a prime.

It is a super-2 number, since 2×114031200132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11403120017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701560006 + 5701560007.

It is an arithmetic number, because the mean of its divisors is an integer number (5701560007).

Almost surely, 211403120013 is an apocalyptic number.

It is an amenable number.

11403120013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11403120013 is an equidigital number, since it uses as much as digits as its factorization.

11403120013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 11403120013 its reverse (31002130411), we get a palindrome (42405250424).

The spelling of 11403120013 in words is "eleven billion, four hundred three million, one hundred twenty thousand, thirteen".