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1140313121403 = 3601632453201
BaseRepresentation
bin10000100101111111111…
…101010110001001111011
311001000100101022112001020
4100211333331112021323
5122140330124341103
62231504055353523
7145246010414511
oct20457775261173
94030311275036
101140313121403
113aa671035855
121650006828a3
13836b99a0b71
143d2974a24b1
151e9debd9753
hex1097ff5627b

1140313121403 has 8 divisors (see below), whose sum is σ = 1522947310416. Its totient is φ = 758943840000.

The previous prime is 1140313121371. The next prime is 1140313121449. The reversal of 1140313121403 is 3041213130411.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1140313121403 - 25 = 1140313121371 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1140313121473) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 316224798 + ... + 316228403.

It is an arithmetic number, because the mean of its divisors is an integer number (190368413802).

Almost surely, 21140313121403 is an apocalyptic number.

1140313121403 is a deficient number, since it is larger than the sum of its proper divisors (382634189013).

1140313121403 is an equidigital number, since it uses as much as digits as its factorization.

1140313121403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 632453805.

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 1140313121403 its reverse (3041213130411), we get a palindrome (4181526251814).

The spelling of 1140313121403 in words is "one trillion, one hundred forty billion, three hundred thirteen million, one hundred twenty-one thousand, four hundred three".

Divisors: 1 3 601 1803 632453201 1897359603 380104373801 1140313121403