Base | Representation |
---|---|
bin | 10000100101111111111… |
… | …101010110111000110111 |
3 | 11001000100101022200011111 |
4 | 100211333331112320313 |
5 | 122140330124440112 |
6 | 2231504055415451 |
7 | 145246010426332 |
oct | 20457775267067 |
9 | 4030311280144 |
10 | 1140313124407 |
11 | 3aa671038036 |
12 | 165000684587 |
13 | 836b99a2342 |
14 | 3d2974a3619 |
15 | 1e9debda5a7 |
hex | 1097ff56e37 |
1140313124407 has 2 divisors, whose sum is σ = 1140313124408. Its totient is φ = 1140313124406.
The previous prime is 1140313124393. The next prime is 1140313124429. The reversal of 1140313124407 is 7044213130411.
It is a weak prime.
It is an emirp because it is prime and its reverse (7044213130411) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1140313124407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1140313124497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570156562203 + 570156562204.
It is an arithmetic number, because the mean of its divisors is an integer number (570156562204).
Almost surely, 21140313124407 is an apocalyptic number.
1140313124407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140313124407 is an equidigital number, since it uses as much as digits as its factorization.
1140313124407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 1140313124407 its reverse (7044213130411), we get a palindrome (8184526254818).
The spelling of 1140313124407 in words is "one trillion, one hundred forty billion, three hundred thirteen million, one hundred twenty-four thousand, four hundred seven".
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