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1140313124407 is a prime number
BaseRepresentation
bin10000100101111111111…
…101010110111000110111
311001000100101022200011111
4100211333331112320313
5122140330124440112
62231504055415451
7145246010426332
oct20457775267067
94030311280144
101140313124407
113aa671038036
12165000684587
13836b99a2342
143d2974a3619
151e9debda5a7
hex1097ff56e37

1140313124407 has 2 divisors, whose sum is σ = 1140313124408. Its totient is φ = 1140313124406.

The previous prime is 1140313124393. The next prime is 1140313124429. The reversal of 1140313124407 is 7044213130411.

It is a weak prime.

It is an emirp because it is prime and its reverse (7044213130411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1140313124407 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1140313124497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570156562203 + 570156562204.

It is an arithmetic number, because the mean of its divisors is an integer number (570156562204).

Almost surely, 21140313124407 is an apocalyptic number.

1140313124407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140313124407 is an equidigital number, since it uses as much as digits as its factorization.

1140313124407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 31.

Adding to 1140313124407 its reverse (7044213130411), we get a palindrome (8184526254818).

The spelling of 1140313124407 in words is "one trillion, one hundred forty billion, three hundred thirteen million, one hundred twenty-four thousand, four hundred seven".