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1140313131143 = 3136784294553
BaseRepresentation
bin10000100101111111111…
…101011000100010000111
311001000100101100000101222
4100211333331120202013
5122140330130144033
62231504055510555
7145246010455064
oct20457775304207
94030311300358
101140313131143
113aa6710420aa
1216500068845b
13836b99a5424
143d2974a5c6b
151e9debdc598
hex1097ff58887

1140313131143 has 4 divisors (see below), whose sum is σ = 1177097425728. Its totient is φ = 1103528836560.

The previous prime is 1140313131127. The next prime is 1140313131197. The reversal of 1140313131143 is 3411313130411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1140313131143 - 24 = 1140313131127 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140313131103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18392147246 + ... + 18392147307.

It is an arithmetic number, because the mean of its divisors is an integer number (294274356432).

Almost surely, 21140313131143 is an apocalyptic number.

1140313131143 is a deficient number, since it is larger than the sum of its proper divisors (36784294585).

1140313131143 is an equidigital number, since it uses as much as digits as its factorization.

1140313131143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36784294584.

The product of its (nonzero) digits is 1296, while the sum is 26.

Adding to 1140313131143 its reverse (3411313130411), we get a palindrome (4551626261554).

The spelling of 1140313131143 in words is "one trillion, one hundred forty billion, three hundred thirteen million, one hundred thirty-one thousand, one hundred forty-three".

Divisors: 1 31 36784294553 1140313131143