1140313340113 has 4 divisors (see below), whose sum is σ = 1144521138688. Its totient is φ = 1136105541540.

The previous prime is 1140313340051. The next prime is 1140313340119. The reversal of 1140313340113 is 3110433130411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1140313340113 - 2¹³ = 1140313331921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1140313340119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2103898881 + ... + 2103899422.

It is an arithmetic number, because the mean of its divisors is an integer number (286130284672).

Almost surely, 2^{1140313340113} is an apocalyptic number.

It is an amenable number.

1140313340113 is a deficient number, since it is larger than the sum of its proper divisors (4207798575).

1140313340113 is an equidigital number, since it uses as much as digits as its factorization.

1140313340113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4207798574.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1140313340113 its reverse (3110433130411), we get a palindrome (4250746470524).

The spelling of 1140313340113 in words is "one trillion, one hundred forty billion, three hundred thirteen million, three hundred forty thousand, one hundred thirteen".