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1140314002022 = 21350986165483
BaseRepresentation
bin10000100110000000000…
…000101101001001100110
311001000100102222021000202
4100212000000231021212
5122140330341031042
62231504130310502
7145246021043066
oct20460000551146
94030312867022
101140314002022
113aa671587438
12165000a28432
13836b9c1b940
143d2976513a6
151e9ded10632
hex1098002d266

1140314002022 has 16 divisors (see below), whose sum is σ = 1845664667280. Its totient is φ = 525264778272.

The previous prime is 1140314002001. The next prime is 1140314002049. The reversal of 1140314002022 is 2202004130411.

It is a junction number, because it is equal to n+sod(n) for n = 1140314001985 and 1140314002003.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43069508 + ... + 43095975.

It is an arithmetic number, because the mean of its divisors is an integer number (115354041705).

Almost surely, 21140314002022 is an apocalyptic number.

1140314002022 is a deficient number, since it is larger than the sum of its proper divisors (705350665258).

1140314002022 is a wasteful number, since it uses less digits than its factorization.

1140314002022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86166007.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 1140314002022 its reverse (2202004130411), we get a palindrome (3342318132433).

The spelling of 1140314002022 in words is "one trillion, one hundred forty billion, three hundred fourteen million, two thousand, twenty-two".

Divisors: 1 2 13 26 509 1018 6617 13234 86165483 172330966 1120151279 2240302558 43858230847 87716461694 570157001011 1140314002022