Base | Representation |
---|---|
bin | 11001111011011000000111… |
… | …110110001011100001101111 |
3 | 112221202022021020011122111122 |
4 | 121323120013312023201233 |
5 | 104421243014404233203 |
6 | 1042305204250211155 |
7 | 33006335126560451 |
oct | 3173300766134157 |
9 | 487668236148448 |
10 | 114031513352303 |
11 | 33374547545878 |
12 | 109580a3123abb |
13 | 4b82182b4a901 |
14 | 20232246a62d1 |
15 | d2b34c0cc538 |
hex | 67b607d8b86f |
114031513352303 has 2 divisors, whose sum is σ = 114031513352304. Its totient is φ = 114031513352302.
The previous prime is 114031513352293. The next prime is 114031513352311. The reversal of 114031513352303 is 303253315130411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114031513352303 - 214 = 114031513335919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114031513352353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57015756676151 + 57015756676152.
It is an arithmetic number, because the mean of its divisors is an integer number (57015756676152).
Almost surely, 2114031513352303 is an apocalyptic number.
114031513352303 is a deficient number, since it is larger than the sum of its proper divisors (1).
114031513352303 is an equidigital number, since it uses as much as digits as its factorization.
114031513352303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48600, while the sum is 35.
Adding to 114031513352303 its reverse (303253315130411), we get a palindrome (417284828482714).
The spelling of 114031513352303 in words is "one hundred fourteen trillion, thirty-one billion, five hundred thirteen million, three hundred fifty-two thousand, three hundred three".
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