Base | Representation |
---|---|
bin | 110101000110011011… |
… | …0010111010001010111 |
3 | 101220100002201112001101 |
4 | 1222030312113101113 |
5 | 3332014221223111 |
6 | 124215150010531 |
7 | 11144552541514 |
oct | 1521466272127 |
9 | 356302645041 |
10 | 114032211031 |
11 | 443a7234a22 |
12 | 1a1251a6a47 |
13 | a9a39b8aab |
14 | 573a92030b |
15 | 2e760d1bc1 |
hex | 1a8cd97457 |
114032211031 has 2 divisors, whose sum is σ = 114032211032. Its totient is φ = 114032211030.
The previous prime is 114032210977. The next prime is 114032211047. The reversal of 114032211031 is 130112230411.
It is a strong prime.
It is an emirp because it is prime and its reverse (130112230411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114032211031 - 215 = 114032178263 is a prime.
It is a super-2 number, since 2×1140322110312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114032217031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57016105515 + 57016105516.
It is an arithmetic number, because the mean of its divisors is an integer number (57016105516).
Almost surely, 2114032211031 is an apocalyptic number.
114032211031 is a deficient number, since it is larger than the sum of its proper divisors (1).
114032211031 is an equidigital number, since it uses as much as digits as its factorization.
114032211031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 114032211031 its reverse (130112230411), we get a palindrome (244144441442).
The spelling of 114032211031 in words is "one hundred fourteen billion, thirty-two million, two hundred eleven thousand, thirty-one".
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