Base | Representation |
---|---|
bin | 110101000110011011… |
… | …1001000111010101101 |
3 | 101220100010002211222212 |
4 | 1222030313020322231 |
5 | 3332014244230011 |
6 | 124215154220205 |
7 | 11144554346414 |
oct | 1521467107255 |
9 | 356303084885 |
10 | 114032414381 |
11 | 443a7363786 |
12 | 1a125284665 |
13 | a9a3a5a512 |
14 | 573a97447b |
15 | 2e7612208b |
hex | 1a8cdc8ead |
114032414381 has 2 divisors, whose sum is σ = 114032414382. Its totient is φ = 114032414380.
The previous prime is 114032414347. The next prime is 114032414477. The reversal of 114032414381 is 183414230411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 113195238025 + 837176356 = 336445^2 + 28934^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114032414381 is a prime.
It is a super-2 number, since 2×1140324143812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114032414281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57016207190 + 57016207191.
It is an arithmetic number, because the mean of its divisors is an integer number (57016207191).
Almost surely, 2114032414381 is an apocalyptic number.
It is an amenable number.
114032414381 is a deficient number, since it is larger than the sum of its proper divisors (1).
114032414381 is an equidigital number, since it uses as much as digits as its factorization.
114032414381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 32.
Adding to 114032414381 its reverse (183414230411), we get a palindrome (297446644792).
The spelling of 114032414381 in words is "one hundred fourteen billion, thirty-two million, four hundred fourteen thousand, three hundred eighty-one".
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