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11403412113 = 33801137371
BaseRepresentation
bin10101001111011001…
…00100001010010001
31002102201112100121210
422213230210022101
5141323233141423
65123314410333
7552405255312
oct124754441221
932381470553
1011403412113
114921a24335
122262b909a9
1310c9692042
147a26c2609
1546b1c8b93
hex2a7b24291

11403412113 has 4 divisors (see below), whose sum is σ = 15204549488. Its totient is φ = 7602274740.

The previous prime is 11403412091. The next prime is 11403412129. The reversal of 11403412113 is 31121430411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11403412113 - 26 = 11403412049 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11403412113.

It is not an unprimeable number, because it can be changed into a prime (11403412193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1900568683 + ... + 1900568688.

It is an arithmetic number, because the mean of its divisors is an integer number (3801137372).

Almost surely, 211403412113 is an apocalyptic number.

It is an amenable number.

11403412113 is a deficient number, since it is larger than the sum of its proper divisors (3801137375).

11403412113 is an equidigital number, since it uses as much as digits as its factorization.

11403412113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3801137374.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 11403412113 its reverse (31121430411), we get a palindrome (42524842524).

The spelling of 11403412113 in words is "eleven billion, four hundred three million, four hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 3801137371 11403412113