11403443131 has 4 divisors (see below), whose sum is σ = 11403656712. Its totient is φ = 11403229552.

The previous prime is 11403443071. The next prime is 11403443147. The reversal of 11403443131 is 13134430411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11403443131 - 2²³ = 11395054523 is a prime.

It is a super-2 number, since 2×11403443131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11403443096 and 11403443105.

It is not an unprimeable number, because it can be changed into a prime (11403443231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52176 + ... + 159778.

It is an arithmetic number, because the mean of its divisors is an integer number (2850914178).

Almost surely, 2^11403443131 is an apocalyptic number.

11403443131 is a deficient number, since it is larger than the sum of its proper divisors (213581).

11403443131 is a wasteful number, since it uses less digits than its factorization.

11403443131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 213580.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11403443131 its reverse (13134430411), we get a palindrome (24537873542).

The spelling of 11403443131 in words is "eleven billion, four hundred three million, four hundred forty-three thousand, one hundred thirty-one".