114034501110132 has 24 divisors (see below), whose sum is σ = 295645002878400. Its totient is φ = 38011500370008.

The previous prime is 114034501110121. The next prime is 114034501110133. The reversal of 114034501110132 is 231011105430411.

114034501110132 is a `hidden beast` number, since 1 + 1 + 4 + 0 + 34 + 501 + 110 + 13 + 2 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 114034501110096 and 114034501110105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114034501110133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 527937505032 + ... + 527937505247.

It is an arithmetic number, because the mean of its divisors is an integer number (12318541786600).

Almost surely, 2^{114034501110132} is an apocalyptic number.

114034501110132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

114034501110132 is an abundant number, since it is smaller than the sum of its proper divisors (181610501768268).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

114034501110132 is a wasteful number, since it uses less digits than its factorization.

114034501110132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1055875010292 (or 1055875010284 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 114034501110132 its reverse (231011105430411), we get a palindrome (345045606540543).

The spelling of 114034501110132 in words is "one hundred fourteen trillion, thirty-four billion, five hundred one million, one hundred ten thousand, one hundred thirty-two".