Base | Representation |
---|---|
bin | 110101000110100001… |
… | …0100111001000100101 |
3 | 101220100022202122022021 |
4 | 1222031002213020211 |
5 | 3332021031443413 |
6 | 124215342503141 |
7 | 11144622043252 |
oct | 1521502471045 |
9 | 356308678267 |
10 | 114035421733 |
11 | 443a90281a2 |
12 | 1a126294ab1 |
13 | a9a457130c |
14 | 573b118429 |
15 | 2e7651818d |
hex | 1a8d0a7225 |
114035421733 has 2 divisors, whose sum is σ = 114035421734. Its totient is φ = 114035421732.
The previous prime is 114035421727. The next prime is 114035421809. The reversal of 114035421733 is 337124530411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 113951479489 + 83942244 = 337567^2 + 9162^2 .
It is an emirp because it is prime and its reverse (337124530411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114035421733 - 25 = 114035421701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114035422733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57017710866 + 57017710867.
It is an arithmetic number, because the mean of its divisors is an integer number (57017710867).
Almost surely, 2114035421733 is an apocalyptic number.
It is an amenable number.
114035421733 is a deficient number, since it is larger than the sum of its proper divisors (1).
114035421733 is an equidigital number, since it uses as much as digits as its factorization.
114035421733 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 34.
The spelling of 114035421733 in words is "one hundred fourteen billion, thirty-five million, four hundred twenty-one thousand, seven hundred thirty-three".
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