114040402121 has 2 divisors, whose sum is σ = 114040402122. Its totient is φ = 114040402120.

The previous prime is 114040402117. The next prime is 114040402123. The reversal of 114040402121 is 121204040411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 59068441600 + 54971960521 = 243040^2 + 234461^2 .

It is a cyclic number.

It is not a de Polignac number, because 114040402121 - 2² = 114040402117 is a prime.

It is a super-4 number, since 4×114040402121⁴ (a number of 45 digits) contains 4444 as substring.

Together with 114040402123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 114040402093 and 114040402102.

It is not a weakly prime, because it can be changed into another prime (114040402123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57020201060 + 57020201061.

It is an arithmetic number, because the mean of its divisors is an integer number (57020201061).

Almost surely, 2^114040402121 is an apocalyptic number.

It is an amenable number.

114040402121 is a deficient number, since it is larger than the sum of its proper divisors (1).

114040402121 is an equidigital number, since it uses as much as digits as its factorization.

114040402121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 256, while the sum is 20.

Adding to 114040402121 its reverse (121204040411), we get a palindrome (235244442532).

The spelling of 114040402121 in words is "one hundred fourteen billion, forty million, four hundred two thousand, one hundred twenty-one".