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11404121 is a prime number
BaseRepresentation
bin101011100000…
…001101011001
3210110101111212
4223200031121
510404412441
61044232505
7165635111
oct53401531
923411455
1011404121
11648a0a3
12399b735
132493a01
14172c041
151003eeb
hexae0359

11404121 has 2 divisors, whose sum is σ = 11404122. Its totient is φ = 11404120.

The previous prime is 11404111. The next prime is 11404139. The reversal of 11404121 is 12140411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10272025 + 1132096 = 3205^2 + 1064^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11404121 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11404096 and 11404105.

It is not a weakly prime, because it can be changed into another prime (11404111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5702060 + 5702061.

It is an arithmetic number, because the mean of its divisors is an integer number (5702061).

Almost surely, 211404121 is an apocalyptic number.

It is an amenable number.

11404121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11404121 is an equidigital number, since it uses as much as digits as its factorization.

11404121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32, while the sum is 14.

The square root of 11404121 is about 3376.9988155165. The cubic root of 11404121 is about 225.0888274787.

Adding to 11404121 its reverse (12140411), we get a palindrome (23544532).

The spelling of 11404121 in words is "eleven million, four hundred four thousand, one hundred twenty-one".