Base | Representation |
---|---|
bin | 1010010111110100000100… |
… | …0110100110101110011011 |
3 | 1111101020022102111201111102 |
4 | 2211331001012212232123 |
5 | 2443321330441441103 |
6 | 40131010420222015 |
7 | 2254633314110411 |
oct | 245750106465633 |
9 | 44336272451442 |
10 | 11404230421403 |
11 | 36a7563846546 |
12 | 134227183a90b |
13 | 64955032cb11 |
14 | 2b5d7950d2b1 |
15 | 14b9b4690e88 |
hex | a5f411a6b9b |
11404230421403 has 4 divisors (see below), whose sum is σ = 11404245290208. Its totient is φ = 11404215552600.
The previous prime is 11404230421399. The next prime is 11404230421447. The reversal of 11404230421403 is 30412403240411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11404230421403 - 22 = 11404230421399 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11404230423403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6217523 + ... + 7840028.
It is an arithmetic number, because the mean of its divisors is an integer number (2851061322552).
Almost surely, 211404230421403 is an apocalyptic number.
11404230421403 is a deficient number, since it is larger than the sum of its proper divisors (14868805).
11404230421403 is an equidigital number, since it uses as much as digits as its factorization.
11404230421403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14868804.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 11404230421403 its reverse (30412403240411), we get a palindrome (41816633661814).
The spelling of 11404230421403 in words is "eleven trillion, four hundred four billion, two hundred thirty million, four hundred twenty-one thousand, four hundred three".
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