Base | Representation |
---|---|
bin | 10000100110000110100… |
… | …101111101001011101101 |
3 | 11001000122010202121011121 |
4 | 100212012211331023231 |
5 | 122141042123232232 |
6 | 2231523113220541 |
7 | 145251531500344 |
oct | 20460645751355 |
9 | 4030563677147 |
10 | 1140424430317 |
11 | 3aa718950897 |
12 | 165031a01751 |
13 | 83706a73c23 |
14 | 3d2a8198b5b |
15 | 1e9e9874d97 |
hex | 1098697d2ed |
1140424430317 has 2 divisors, whose sum is σ = 1140424430318. Its totient is φ = 1140424430316.
The previous prime is 1140424430281. The next prime is 1140424430339. The reversal of 1140424430317 is 7130344240411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1052113827076 + 88310603241 = 1025726^2 + 297171^2 .
It is a cyclic number.
It is not a de Polignac number, because 1140424430317 - 215 = 1140424397549 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1140424430617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570212215158 + 570212215159.
It is an arithmetic number, because the mean of its divisors is an integer number (570212215159).
Almost surely, 21140424430317 is an apocalyptic number.
It is an amenable number.
1140424430317 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140424430317 is an equidigital number, since it uses as much as digits as its factorization.
1140424430317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32256, while the sum is 34.
Adding to 1140424430317 its reverse (7130344240411), we get a palindrome (8270768670728).
The spelling of 1140424430317 in words is "one trillion, one hundred forty billion, four hundred twenty-four million, four hundred thirty thousand, three hundred seventeen".
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