Base | Representation |
---|---|
bin | 11001111011100010111011… |
… | …001000010010000101111111 |
3 | 112221210102012111111000120101 |
4 | 121323202323020102011333 |
5 | 104421440242423412142 |
6 | 1042314403151301531 |
7 | 33010225415345515 |
oct | 3173427310220577 |
9 | 487712174430511 |
10 | 114043111154047 |
11 | 3337945916a999 |
12 | 1095a39b21a8a7 |
13 | 4b832b08813aa |
14 | 2023a04b0a4b5 |
15 | d2b7ca3a30b7 |
hex | 67b8bb21217f |
114043111154047 has 2 divisors, whose sum is σ = 114043111154048. Its totient is φ = 114043111154046.
The previous prime is 114043111154039. The next prime is 114043111154069. The reversal of 114043111154047 is 740451111340411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114043111154047 - 23 = 114043111154039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114043111153997 and 114043111154015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114043111154017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57021555577023 + 57021555577024.
It is an arithmetic number, because the mean of its divisors is an integer number (57021555577024).
Almost surely, 2114043111154047 is an apocalyptic number.
114043111154047 is a deficient number, since it is larger than the sum of its proper divisors (1).
114043111154047 is an equidigital number, since it uses as much as digits as its factorization.
114043111154047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 37.
Adding to 114043111154047 its reverse (740451111340411), we get a palindrome (854494222494458).
The spelling of 114043111154047 in words is "one hundred fourteen trillion, forty-three billion, one hundred eleven million, one hundred fifty-four thousand, forty-seven".
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