Base | Representation |
---|---|
bin | 10101001111100000… |
… | …00100110101110011 |
3 | 1002102210021010000121 |
4 | 22213300010311303 |
5 | 141324002114103 |
6 | 5123350231111 |
7 | 552416140342 |
oct | 124760046563 |
9 | 32383233017 |
10 | 11404332403 |
11 | 49224a2802 |
12 | 2263355497 |
13 | 10c9924ba9 |
14 | 7a2881b59 |
15 | 46b30b6bd |
hex | 2a7c04d73 |
11404332403 has 2 divisors, whose sum is σ = 11404332404. Its totient is φ = 11404332402.
The previous prime is 11404332383. The next prime is 11404332449. The reversal of 11404332403 is 30423340411.
11404332403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11404332403 - 233 = 2814397811 is a prime.
It is not a weakly prime, because it can be changed into another prime (11404332493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5702166201 + 5702166202.
It is an arithmetic number, because the mean of its divisors is an integer number (5702166202).
Almost surely, 211404332403 is an apocalyptic number.
11404332403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11404332403 is an equidigital number, since it uses as much as digits as its factorization.
11404332403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 11404332403 its reverse (30423340411), we get a palindrome (41827672814).
The spelling of 11404332403 in words is "eleven billion, four hundred four million, three hundred thirty-two thousand, four hundred three".
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