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114043441133 is a prime number
BaseRepresentation
bin110101000110110000…
…1001100111111101101
3101220100212212001212002
41222031201030333231
53332030110104013
6124220230422045
711145050153366
oct1521541147755
9356325761762
10114043441133
11444026052a6
121a128b01925
13a9a611b51b
14573c204b6d
152e7709e358
hex1a8d84cfed

114043441133 has 2 divisors, whose sum is σ = 114043441134. Its totient is φ = 114043441132.

The previous prime is 114043441123. The next prime is 114043441147. The reversal of 114043441133 is 331144340411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81465718084 + 32577723049 = 285422^2 + 180493^2 .

It is a cyclic number.

It is not a de Polignac number, because 114043441133 - 24 = 114043441117 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 114043441096 and 114043441105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114043441103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57021720566 + 57021720567.

It is an arithmetic number, because the mean of its divisors is an integer number (57021720567).

Almost surely, 2114043441133 is an apocalyptic number.

It is an amenable number.

114043441133 is a deficient number, since it is larger than the sum of its proper divisors (1).

114043441133 is an equidigital number, since it uses as much as digits as its factorization.

114043441133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 114043441133 its reverse (331144340411), we get a palindrome (445187781544).

The spelling of 114043441133 in words is "one hundred fourteen billion, forty-three million, four hundred forty-one thousand, one hundred thirty-three".