Base | Representation |
---|---|
bin | 11001111011100011001110… |
… | …110011111000011010101101 |
3 | 112221210110001111210201200212 |
4 | 121323203032303320122231 |
5 | 104421441431441202232 |
6 | 1042314500024432205 |
7 | 33010236535102043 |
oct | 3173431663703255 |
9 | 487713044721625 |
10 | 114043441350317 |
11 | 33379608599276 |
12 | 1095a471918665 |
13 | 4b833340c25bb |
14 | 2023a36900393 |
15 | d2b7e9378eb2 |
hex | 67b8cecf86ad |
114043441350317 has 2 divisors, whose sum is σ = 114043441350318. Its totient is φ = 114043441350316.
The previous prime is 114043441350301. The next prime is 114043441350341. The reversal of 114043441350317 is 713053144340411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 112084801914121 + 1958639436196 = 10587011^2 + 1399514^2 .
It is a cyclic number.
It is not a de Polignac number, because 114043441350317 - 24 = 114043441350301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114043441358317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57021720675158 + 57021720675159.
It is an arithmetic number, because the mean of its divisors is an integer number (57021720675159).
Almost surely, 2114043441350317 is an apocalyptic number.
It is an amenable number.
114043441350317 is a deficient number, since it is larger than the sum of its proper divisors (1).
114043441350317 is an equidigital number, since it uses as much as digits as its factorization.
114043441350317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 41.
Adding to 114043441350317 its reverse (713053144340411), we get a palindrome (827096585690728).
The spelling of 114043441350317 in words is "one hundred fourteen trillion, forty-three billion, four hundred forty-one million, three hundred fifty thousand, three hundred seventeen".
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