11404401304131 has 12 divisors (see below), whose sum is σ = 17970571752120. Its totient is φ = 6911758366080.

The previous prime is 11404401304099. The next prime is 11404401304189. The reversal of 11404401304131 is 13140310440411.

11404401304131 is a `hidden beast` number, since 1 + 140 + 440 + 13 + 0 + 41 + 31 = 666.

11404401304131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11404401304131 - 2⁵ = 11404401304099 is a prime.

It is a super-2 number, since 2×11404401304131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11404401304095 and 11404401304104.

It is not an unprimeable number, because it can be changed into a prime (11404401304031) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 57597986286 + ... + 57597986483.

It is an arithmetic number, because the mean of its divisors is an integer number (1497547646010).

Almost surely, 2^{11404401304131} is an apocalyptic number.

11404401304131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

11404401304131 is a deficient number, since it is larger than the sum of its proper divisors (6566170447989).

11404401304131 is a wasteful number, since it uses less digits than its factorization.

11404401304131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115195972786 (or 115195972783 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 11404401304131 its reverse (13140310440411), we get a palindrome (24544711744542).

The spelling of 11404401304131 in words is "eleven trillion, four hundred four billion, four hundred one million, three hundred four thousand, one hundred thirty-one".