Base | Representation |
---|---|
bin | 110101000111000011… |
… | …1101111010001101001 |
3 | 101220101120212022000221 |
4 | 1222032013233101221 |
5 | 3332040201334032 |
6 | 124221231130041 |
7 | 11145232056061 |
oct | 1521607572151 |
9 | 356346768027 |
10 | 114053543017 |
11 | 44408284a67 |
12 | 1a130373921 |
13 | a9a824757b |
14 | 573d6b43a1 |
15 | 2e77de7597 |
hex | 1a8e1ef469 |
114053543017 has 2 divisors, whose sum is σ = 114053543018. Its totient is φ = 114053543016.
The previous prime is 114053542991. The next prime is 114053543117. The reversal of 114053543017 is 710345350411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 81862365456 + 32191177561 = 286116^2 + 179419^2 .
It is a cyclic number.
It is not a de Polignac number, because 114053543017 - 211 = 114053540969 is a prime.
It is not a weakly prime, because it can be changed into another prime (114053543117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57026771508 + 57026771509.
It is an arithmetic number, because the mean of its divisors is an integer number (57026771509).
Almost surely, 2114053543017 is an apocalyptic number.
It is an amenable number.
114053543017 is a deficient number, since it is larger than the sum of its proper divisors (1).
114053543017 is an equidigital number, since it uses as much as digits as its factorization.
114053543017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 34.
Adding to 114053543017 its reverse (710345350411), we get a palindrome (824398893428).
The spelling of 114053543017 in words is "one hundred fourteen billion, fifty-three million, five hundred forty-three thousand, seventeen".
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