114053543117 has 2 divisors, whose sum is σ = 114053543118. Its totient is φ = 114053543116.

The previous prime is 114053543017. The next prime is 114053543147. The reversal of 114053543117 is 711345350411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113792203561 + 261339556 = 337331^2 + 16166^2 .

It is a cyclic number.

It is not a de Polignac number, because 114053543117 - 2¹⁴ = 114053526733 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114053543147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57026771558 + 57026771559.

It is an arithmetic number, because the mean of its divisors is an integer number (57026771559).

Almost surely, 2^114053543117 is an apocalyptic number.

It is an amenable number.

114053543117 is a deficient number, since it is larger than the sum of its proper divisors (1).

114053543117 is an equidigital number, since it uses as much as digits as its factorization.

114053543117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 35.

Adding to 114053543117 its reverse (711345350411), we get a palindrome (825398893528).

The spelling of 114053543117 in words is "one hundred fourteen billion, fifty-three million, five hundred forty-three thousand, one hundred seventeen".