Base | Representation |
---|---|
bin | 110101000111010000… |
… | …1111010011000100111 |
3 | 101220102001202212220011 |
4 | 1222032201322120213 |
5 | 3332043430414023 |
6 | 124222034151051 |
7 | 11145344303521 |
oct | 1521641723047 |
9 | 356361685804 |
10 | 114060404263 |
11 | 44411140a13 |
12 | 1a132722487 |
13 | a9a97aa590 |
14 | 574057ca11 |
15 | 2e7880050d |
hex | 1a8e87a627 |
114060404263 has 16 divisors (see below), whose sum is σ = 125898336256. Its totient is φ = 102668277600.
The previous prime is 114060404261. The next prime is 114060404291. The reversal of 114060404263 is 362404060411.
It is a cyclic number.
It is not a de Polignac number, because 114060404263 - 21 = 114060404261 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114060404261) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 171238 + ... + 507388.
It is an arithmetic number, because the mean of its divisors is an integer number (7868646016).
Almost surely, 2114060404263 is an apocalyptic number.
114060404263 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
114060404263 is a deficient number, since it is larger than the sum of its proper divisors (11837931993).
114060404263 is a wasteful number, since it uses less digits than its factorization.
114060404263 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 336814.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 114060404263 its reverse (362404060411), we get a palindrome (476464464674).
The spelling of 114060404263 in words is "one hundred fourteen billion, sixty million, four hundred four thousand, two hundred sixty-three".
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